勉強のためにListのAPIはなるべく使わない方向。
// P25 (*) Generate a random permutation of the elements of a list. // Hint: Use the solution of problem P23. // Example: // scala> randomPermute(List('a, 'b, 'c, 'd, 'e, 'f)) // res0: List[Symbol] = List('b, 'a, 'd, 'c, 'e, 'f) // P20 (*) Remove the Kth element from a list. def removeAt[T](i: Int, xs: List[T]) = { def r(i: Int, xs: List[T], acc: List[T]): (List[T], T) = (i, xs) match { case (0, h :: t) => (acc.reverse ::: t, h) case (i, h :: t) => r(i - 1, t, h :: acc) } if(i < 0 || xs.size <= i) throw new NoSuchElementException else r(i, xs, Nil) } import scala.util.Random def randomPermute[T](xs: List[T]) = { val rand = new Random def r(ys: List[T], acc: List[T]): List[T] = { if(ys.size == 1) ys.head :: acc else { val (rest, removed) = removeAt(rand.nextInt(ys.size), ys) r(rest, removed :: acc) } } if(xs.isEmpty) Nil else r(xs, Nil) }解答例
またもや、してやられたぜ!
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